Which equation determines the required heat transfer surface area to achieve a given heat transfer rate, accounting for losses with U and the inlet/outlet temperatures?

Study for the EPRI Heat Transfer and Fluid Flow Test. Prepare with flashcards and multiple choice questions, each with hints and explanations. Get ready for your exam!

Multiple Choice

Which equation determines the required heat transfer surface area to achieve a given heat transfer rate, accounting for losses with U and the inlet/outlet temperatures?

Explanation:
Sizing a heat transfer surface uses a single relationship that ties the heat rate to the area, the overall transfer capability, and the driving temperature difference between the streams. The appropriate equation is Q = U A ΔT_lm, where U is the overall heat transfer coefficient, A is the surface area, and ΔT_lm is the log-mean temperature difference based on the inlet and outlet temperatures of the two fluids. This form directly shows how to pick the required area to achieve a specified heat transfer rate, since you can rearrange it to A = Q / (U ΔT_lm). The other ideas focus on different heat transfer ideas. Fourier’s law deals with conduction through a solid (q = kA dT/dx) and isn’t the sizing relation for a surface exchanging heat between fluids. Newton’s law of cooling describes convective exchange at a surface with a single fluid (q = h A (T_s - T∞)) and doesn’t incorporate the two-fluid driving force via a log-mean temperature difference. The continuity equation is about mass conservation, not heat transfer.

Sizing a heat transfer surface uses a single relationship that ties the heat rate to the area, the overall transfer capability, and the driving temperature difference between the streams. The appropriate equation is Q = U A ΔT_lm, where U is the overall heat transfer coefficient, A is the surface area, and ΔT_lm is the log-mean temperature difference based on the inlet and outlet temperatures of the two fluids. This form directly shows how to pick the required area to achieve a specified heat transfer rate, since you can rearrange it to A = Q / (U ΔT_lm).

The other ideas focus on different heat transfer ideas. Fourier’s law deals with conduction through a solid (q = kA dT/dx) and isn’t the sizing relation for a surface exchanging heat between fluids. Newton’s law of cooling describes convective exchange at a surface with a single fluid (q = h A (T_s - T∞)) and doesn’t incorporate the two-fluid driving force via a log-mean temperature difference. The continuity equation is about mass conservation, not heat transfer.

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